I’m running a FEA on a plate bolted in and a distributed load applied upon it. I know that the holes will provide stress concentrations but I need to know the maximum stress that will cause the specimen to fracture.
Thank you!
I’m running a FEA on a plate bolted in and a distributed load applied upon it. I know that the holes will provide stress concentrations but I need to know the maximum stress that will cause the specimen to fracture.
Thank you!
Hi @tsloan,
a good and easy approach for this has already been mentioned by @rszoeke in this post: Show Overload of a structure
Let me know how things go!
All the best,
Jousef
Thank you. Do you know how he links the von_Mises_stress for the factory of safety calculation?
Hi @tsloan,
the factor of safety equals \frac{\text{Yield stress}}{\text{v. Mises stress}} as stated in the post.
Is that what you wanted to know?
Cheers,
Jousef
I understand that but if you look at the link you posted. He creates a calculation in the post processing tab and links the von Mises stress data points to create a visual showing the factors of safety throughout the object. How does he link the function for the von Mises stress?
Ex. His says something like
4e8/von_Mises_stress and that is the function in his calculator filter.
edit: Also i’m going to make my project public but i’m running a pressure test on a symmetrical rectangle plate with the holes fixed and for some reason the von mises stress field is showing a high stress concentration around one of the holes. However, theoretically wouldn’t it make sense for all of the holes to experience the same stress?
Hi @tsloan,
for the facor of safety calculation you need to know he yield stress (or a similar measure that of your material tells you when your material “fails”), then you can calculate the FOS easily in the online post-processor (assuming you have only one material). Just do the following steps:
Now you can choose a new solution field called “Factor Of Safety” and visualize it:
Hope this clears things up.
Best,
Richard
Yes that ended up working, thank you. Is there a simple way to invert the scale just for a better visual?
Add a “-” in front of your formula. All values will be negative but at least you have the scale inverted.
Best,
Richard