I want to move the heat source across the length of the cylinder. I am not able to figure out how to do this? The problem is if I choose surface heat flux, then I have to choose a surface of the cylinder but I do not know how my equation works then. Does anyone have any suggestions?
Hi @nnandakumar,
Please post a appropriate title. I’ve changed it for you.
Project links should be in the post itself. Your project is here for everyone’s reference.
CHT is not my main area so maybe @jousefm or the other users can give you some advice. If I find anything I will be sure to post.
Cheers.
Regards,
Barry
Thank you for the help 
Hi @nnandakumar and @Get_Barried!
Not sure if you are looking for something like this: Thermal benchmark (steady state) - assuming that you have a cylinder and you want to validate your results.
Best,
Jousef
I want to do something similar to this:
but on the outer surface of a cylinder.
Hi @nnandakumar!
The project seems to be private - change the settings that we can see it or share it with us by using the username or mail address.
Cheers,
Jousef
Hey I changed it. You can see it now.
Hi @nnandakumar!
q = \frac{2P}{\pi r_0^2} exp\left(-\frac{2r^2}{r_0^2} \right)
- P is the power of laser, 2 kW in our case.
- r_o is the radius of laser beam, 0.003 m (3 mm) in our case.
- r = \sqrt{(x-x_o)^2+(y-y_o)^2} is the radial distance of the beam from any point. Here, x and y are x and y direction of the coordinate system respectively. xo and yo are the terms used for defining the motion. In our case, x_o = a + R*cos(2 \pi v_\alpha t) and y_o = b + R sin(2\pi v_α t), where;
- a and b are the x and y coordinates of the circle center, in our case (a,b)=(0,0).
- R is the radius of the circle, 0.035 m (3.5 cm) in our case.
- v_\alpha is the angular velocity of the beam, 0.167 \frac{rad}{s} in our case. The actual velocity of the beam can be calculated by v = 2\pi R v_\alpha which gives v ~ 0.037 \frac{m}{s} (~2.22 \frac{m}{min}.)
- t is time step which is 6 s for a full revolution with timestep length of 0.06 s in our case i.e. cos(2\pi) and sin(2\pi) occurs when v_\alpha*t = 0.167 \frac{rad}{s} x 6 s = 1 rad
Does this help? Cheers!
Jousef
I tried to use this equation but since I want to make the beam have helical motion on the outer surface of the cylinder, I am confused as to how to modify the equation and what coordinate system to use :(. I want to first start by just moving the beam in a straight line on the outer curved surface of the cylinder and then introduce also a circular motion. I hope that I am able to explain my idea clearly.
Sorry for the late response @nnandakumar!
I hope that I can have a look at your project later this day and get back to you as soon as know more.
Best,
Jousef
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was anyone able to find something out ?
Did not have the time so far @nnandakumar.
Let me tag my colleagues @BenLewis and @cjquijano here who might jump in in the meantime.
Best,
Jousef
Like this but on a cylinder.